What is the potential difference between two points, if 2J of work must be done to move a 4 mC charge from one point to another is:
A. 50 V
B. 500 V
C.5 V
D. 5000 V
Answer
632.4k+ views
Hint: To solve this problem, use the formula for work done to move a charge from one point to another in terms of potential difference and charge on the particle. Substitute the given values in the formula and solve it to find the potential difference between two points, if 2J of work must be done to move a 4 mC charge from one point to another.
Formula used:
$W= V \times Q$
Complete step-by-step solution:
Given:
Work done. W= 2J
Charge, $C= 4 mC= 4 \times {10}^{-3} C$
The formula for work done to move a charge from one point to another is given by,
$W= V \times Q$ …(1)
Where,
W is the work done to move a charge
V is the potential difference
Q is the charge of the particle
Substituting values in the equation. (1) we get,
$2= V \times 4 \times {10}^{-3}$
$\Rightarrow V= \dfrac {2}{4 \times {10}^{-3} }$
$\Rightarrow V= 0.5 \times {10}^{3}$
$\Rightarrow V= 500 V$
Thus, the potential difference between two points, if 2J of work must be done to move a 4 mC charge from one point to another is 500 V.
So, the correct answer is option B i.e. 500 V.
Note:
To solve these types of questions, students must have a clear knowledge about the concept of electrostatic force. Work done by a field in moving a charge from point to another is directly proportional to the change in the potential energy. Also, the work done by the force or the field on the charged particle will be independent of the path taken by the charge.
Formula used:
$W= V \times Q$
Complete step-by-step solution:
Given:
Work done. W= 2J
Charge, $C= 4 mC= 4 \times {10}^{-3} C$
The formula for work done to move a charge from one point to another is given by,
$W= V \times Q$ …(1)
Where,
W is the work done to move a charge
V is the potential difference
Q is the charge of the particle
Substituting values in the equation. (1) we get,
$2= V \times 4 \times {10}^{-3}$
$\Rightarrow V= \dfrac {2}{4 \times {10}^{-3} }$
$\Rightarrow V= 0.5 \times {10}^{3}$
$\Rightarrow V= 500 V$
Thus, the potential difference between two points, if 2J of work must be done to move a 4 mC charge from one point to another is 500 V.
So, the correct answer is option B i.e. 500 V.
Note:
To solve these types of questions, students must have a clear knowledge about the concept of electrostatic force. Work done by a field in moving a charge from point to another is directly proportional to the change in the potential energy. Also, the work done by the force or the field on the charged particle will be independent of the path taken by the charge.
Recently Updated Pages
Which of the following graphs shows the variation of class 12 physics CBSE

Draw a labelled diagram of the human male reproductive class 12 biology CBSE

Describe the experiment to compare the emf of two cells class 12 physics CBSE

What is standard hydrogen electrode

What is conventional current and electric current class 12 physics CBSE

2Bromopentane is treated with an alcoholic KOH solution class 12 chemistry CBSE

Trending doubts
Draw a labelled sketch of the human eye class 12 physics CBSE

Which are the Top 10 Largest Countries of the World?

A member of Simon commission later became Prime Minister class 12 social science CBSE

Draw ray diagrams each showing i myopic eye and ii class 12 physics CBSE

Give one example of a reptile that is viviparous class 12 biology CBSE

Which is the correct genotypic ratio of mendel dihybrid class 12 biology CBSE

