How do you solve $2\left( {x + 7} \right) + x = 20$ ?
Answer
623.4k+ views
Hint: Here, the given equation is a linear equation having variable \[x\]. We have to calculate the particular value of variable $x$ which satisfies the given linear equation. Firstly, we have to simplify the expression on the LHS (left hand side) of the given equation by following the rule of “BODMAS” and putting variables together and the numerals together. Then, equate the result with the expression given on the RHS (right hand side) and on solving we get the required value of variable $x$.
Complete step by step answer:
Here, the given equation is $2\left( {x + 7} \right) + x = 20$.
The LHS (left hand side) of the equation is $2\left( {x + 7} \right) + x$.
Here, the operators are bracket and addition. by applying the rule of “BODMAS” we have to simplify this expression. We get,
$
= 2\left( {x + 7} \right) + x \\
= 2x + 14 + x \\
= 3x + 14
$
Now, equating this result with RHS (right hand side) of the equation. We get,
$
\Rightarrow 3x + 14 = 20 \\
\Rightarrow 3x = 20 - 14 \\
\Rightarrow 3x = 6 \\
\Rightarrow x = \dfrac{6}{3} \\
\therefore x = 2
$
Thus, the value of variable $x = 2$ satisfy the given equation $2\left( {x + 7} \right) + x = 20$.
Note: If more than one operator is present in a given expression then firstly, we have to perform the operation of the bracket, then perform the operation of ‘$of$’, then perform the operation of division, then perform the operation of multiplication, then perform the operation of addition and finally perform the operation of subtraction.
The operator ‘$of$’ simply means multiplication. But if both the operator ‘$of$’ and multiplication are present in a single expression then firstly we have to perform the operation of ‘$of$’ then the operation of multiplication.
Complete step by step answer:
Here, the given equation is $2\left( {x + 7} \right) + x = 20$.
The LHS (left hand side) of the equation is $2\left( {x + 7} \right) + x$.
Here, the operators are bracket and addition. by applying the rule of “BODMAS” we have to simplify this expression. We get,
$
= 2\left( {x + 7} \right) + x \\
= 2x + 14 + x \\
= 3x + 14
$
Now, equating this result with RHS (right hand side) of the equation. We get,
$
\Rightarrow 3x + 14 = 20 \\
\Rightarrow 3x = 20 - 14 \\
\Rightarrow 3x = 6 \\
\Rightarrow x = \dfrac{6}{3} \\
\therefore x = 2
$
Thus, the value of variable $x = 2$ satisfy the given equation $2\left( {x + 7} \right) + x = 20$.
Note: If more than one operator is present in a given expression then firstly, we have to perform the operation of the bracket, then perform the operation of ‘$of$’, then perform the operation of division, then perform the operation of multiplication, then perform the operation of addition and finally perform the operation of subtraction.
The operator ‘$of$’ simply means multiplication. But if both the operator ‘$of$’ and multiplication are present in a single expression then firstly we have to perform the operation of ‘$of$’ then the operation of multiplication.
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