Solve
\[5x - 5 = 20\]
Answer
567.9k+ views
Hint: Here we have a linear equation with one variable. In this, the variable is ‘x’. In the given problem we need to solve this for ‘x’. We can solve this using the transposition method. That is we group the ‘x’ terms on one side and constants on the other side of the equation.
Complete step-by-step answer:
Given, \[5x - 5 = 20\].
We transpose ‘-5’ which is present on the left-hand side of the equation to the right-hand side of the equation by adding ‘5’ on the right-hand side of the equation.
\[5x = 20 + 5\]
\[5x = 25\]
Similarly, we transpose 5 to the right hand side of the equation by dividing 5 on the right-hand side of the equation.
\[x = \dfrac{{25}}{5}\]
\[ \Rightarrow x = 5\].This is the required answer.
Note: We can check whether the obtained solution is correct or wrong. All we need to do is substituting the value of ‘x’ in the given problem.
\[5x - 5 = 20\]
\[5(5) - 5 = 20\]
\[25 - 5 = 20\]
Simplifying we have,
\[ \Rightarrow 20 = 20\].
That is LHS=RHS. Hence the obtained is correct.
In the above, we did the transpose of addition and subtraction. Similarly, if we have multiplication we use division to transpose. If we have division we use multiplication to transpose. Follow the same procedure for these kinds of problems.
Complete step-by-step answer:
Given, \[5x - 5 = 20\].
We transpose ‘-5’ which is present on the left-hand side of the equation to the right-hand side of the equation by adding ‘5’ on the right-hand side of the equation.
\[5x = 20 + 5\]
\[5x = 25\]
Similarly, we transpose 5 to the right hand side of the equation by dividing 5 on the right-hand side of the equation.
\[x = \dfrac{{25}}{5}\]
\[ \Rightarrow x = 5\].This is the required answer.
Note: We can check whether the obtained solution is correct or wrong. All we need to do is substituting the value of ‘x’ in the given problem.
\[5x - 5 = 20\]
\[5(5) - 5 = 20\]
\[25 - 5 = 20\]
Simplifying we have,
\[ \Rightarrow 20 = 20\].
That is LHS=RHS. Hence the obtained is correct.
In the above, we did the transpose of addition and subtraction. Similarly, if we have multiplication we use division to transpose. If we have division we use multiplication to transpose. Follow the same procedure for these kinds of problems.
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