How do you solve inequalities $5 - 3c \leqslant c + 17$ ?
Answer
616.5k+ views
Hint: For the given inequality $5 - 3c \leqslant c + 17$ , we have to solve for $c$ . We just need to remember to apply all of our operations to both the parts, like adding , subtracting , multiplying, and dividing . Signs get reversed only when we multiply or divide each side by a negative number.
Complete step by step solution:
The given inequality is $5 - 3c \leqslant c + 17$ .
We just need to remember to apply all of our operations to both the parts.
Subtract $ - 5$ from both the side of the inequality ,
$ \Rightarrow 5 - 3c - 5 \leqslant c + 17 - 5$
$ \Rightarrow - 3c \leqslant c + 12$
We can also write it as ,
$ \Rightarrow c + 12 \geqslant - 3c$
Add $3c$both the side of the inequality ,
$ \Rightarrow c + 12 + 3c \geqslant - 3c + 3c$
$ \Rightarrow 4c + 12 \geqslant 0$
Subtract $12$ from both the side of the inequality ,
$ \Rightarrow 4c + 12 - 12 \geqslant - 12$
$ \Rightarrow 4c \geqslant - 12$
Divide both the side of the inequality by $4$,
$
\Rightarrow \dfrac{{4c}}{4} \geqslant \dfrac{{ - 12}}{4} \\
\Rightarrow c \geqslant - 3 \\
$
$ \Rightarrow c \geqslant - 3$
Therefore $c \in [ - 3,\infty )$ .
Additional Informational: Inequalities are often manipulated like equations and follow terribly similar rules, however there's one necessary exception. If you add constant variety to each side of given inequality , the inequality remains true. If you subtract constant variety from each side of the given inequality , the inequality remains true. If you multiply or divide each side of the given inequality by constant positive variety, the inequality remains true.
However, if you multiply or divide each side of the given inequality by a negative variety, the inequality isn't any longer true. In fact, the inequality becomes reversed. This can be quite simple to visualize as a result of we will write that $4 > 2$ . However, if we tend to multiply each side of this inequality by a negative number, we've got to reverse the inequality , giving $ - 4 < - 2$ in order for it to be true.
Note: In inequality:
i) You can add constant amount to every aspect
ii) You can subtract constant amount from both sides
iii) You can multiply or divide both sides by a constant positive amount .
iv) If you multiply or divide both sides by a negative amount, the inequality needs to be reversed.
Complete step by step solution:
The given inequality is $5 - 3c \leqslant c + 17$ .
We just need to remember to apply all of our operations to both the parts.
Subtract $ - 5$ from both the side of the inequality ,
$ \Rightarrow 5 - 3c - 5 \leqslant c + 17 - 5$
$ \Rightarrow - 3c \leqslant c + 12$
We can also write it as ,
$ \Rightarrow c + 12 \geqslant - 3c$
Add $3c$both the side of the inequality ,
$ \Rightarrow c + 12 + 3c \geqslant - 3c + 3c$
$ \Rightarrow 4c + 12 \geqslant 0$
Subtract $12$ from both the side of the inequality ,
$ \Rightarrow 4c + 12 - 12 \geqslant - 12$
$ \Rightarrow 4c \geqslant - 12$
Divide both the side of the inequality by $4$,
$
\Rightarrow \dfrac{{4c}}{4} \geqslant \dfrac{{ - 12}}{4} \\
\Rightarrow c \geqslant - 3 \\
$
$ \Rightarrow c \geqslant - 3$
Therefore $c \in [ - 3,\infty )$ .
Additional Informational: Inequalities are often manipulated like equations and follow terribly similar rules, however there's one necessary exception. If you add constant variety to each side of given inequality , the inequality remains true. If you subtract constant variety from each side of the given inequality , the inequality remains true. If you multiply or divide each side of the given inequality by constant positive variety, the inequality remains true.
However, if you multiply or divide each side of the given inequality by a negative variety, the inequality isn't any longer true. In fact, the inequality becomes reversed. This can be quite simple to visualize as a result of we will write that $4 > 2$ . However, if we tend to multiply each side of this inequality by a negative number, we've got to reverse the inequality , giving $ - 4 < - 2$ in order for it to be true.
Note: In inequality:
i) You can add constant amount to every aspect
ii) You can subtract constant amount from both sides
iii) You can multiply or divide both sides by a constant positive amount .
iv) If you multiply or divide both sides by a negative amount, the inequality needs to be reversed.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

