How do you solve the equation \[\cos A = \dfrac{3}{{19}}\] ?

Hint: Here we have to determine the value, and the given function is an inverse trigonometry. The cos is a cosine trigonometry. We simplify the term which is present in RHS and by using the table of trigonometry ratios for the standard angles and by the scientific calculator or by the Clark’s table we determine the solution for the question.

Complete step by step solution:
The sine, cosine, tangent, cosecant, secant and cotangent are the trigonometry ratios of trigonometry. It is abbreviated as sin, cos, tan, cosec, sec and cot. Here in this question, we have \[\cos A = \dfrac{3}{{19}}\]
Taking the cos to the RHS, the trigonometry ratio will become the inverse. So we have
 \[ \Rightarrow A = {\cos ^{ - 1}}\left( {\dfrac{3}{{19}}} \right)\]
where \[{\cos ^{ - 1}}\] represents the inverse of a cosine function. So we have to find the \[{\cos ^{ - 1}}\left( {\dfrac{3}{{19}}} \right)\] .
We consider the table of trigonometry ratios for standard angles.
The table of cosine function for standard angles is given as



Now consider the given function
 \[{\cos ^{ - 1}}\left( {\dfrac{3}{{19}}} \right)\]
When we consider the fraction term and if we simplify the fraction term we obtain 0.15789.
So according to the table the value will be less than 30.
When we find the value by using the scientific calculator or Clark’s table the value of \[{\cos ^{ - 1}}\left( {\dfrac{3}{{19}}} \right)\] is \[0.99999\] with 5 decimal places and we round off the number it is nearly equal to 1

Note: The trigonometry and inverse trigonometry are inverse for each other. The inverse of a function is represented as the arc of the function or the function is raised by the power -1. For the trigonometry and the inverse trigonometry we need to know about the table of trigonometry ratios for the standard angles.