How do you solve the following system \[4x + 3y = 36\], \[4x + 2y = 10\].

Hint: In this question we have to find the unknown values that are \[x\] and \[y\] solving these equations by using the elimination method. In elimination methods either we add or subtract the equations to find the unknown.

Complete step by step answer:
Let us consider the equation and we will name it as (1) and (2)
\[4x + 3y = 36\]-------(1)
\[\Rightarrow 4x + 2y = 10\]-------(2)
Since the coordinates of \[x\] are same and we change the sign by the alternate sign and we simplify to known the unknown value \[y\]
\[\underline
+ 4x + 3y = 36 \\
\mathop + \limits_{( - )} 4x\mathop + \limits_{( - )} 2y = \mathop + \limits_{( - )} 10 \\ \]
Now we cancel the \[x\] term so we have
\[\underline
+ 4x + 3y = 36 \\
\mathop + \limits_{( - )} 4x\mathop + \limits_{( - )} 2y = \mathop + \limits_{( - )} 10 \\
\\
\Rightarrow y = 26 \\
\]
We have found the value of \[y\] now we have to find the value of \[x\] . so we will substitute the value \[y\] to any one of the equation (1) or (2) . we will substitute the value of \[y\] to equation (1).
Therefore, we have \[4x + 3y = 36\]
\[ \Rightarrow 4x + 3(26) = 36\]
\[ \Rightarrow 4x + 78 = 36\]
\[\Rightarrow 4x = 36 - 78 \\
\Rightarrow 4x = - 42 \\ \]
Divide the above equation by 4 we have
\[ x = \dfrac{{ - 42}}{4} = \dfrac{{ - 21}}{2}\]
Hence we got the unknown values \[x\] and \[y\] that are \[\dfrac{{ - 21}}{2}\] and \[26\] respectively. We can check whether these values are correct or not by substituting the unknown values in the given equations and we have to prove L.H.S is equal to R.H.S.Now we will substitute the value of \[x\] and \[y\] in equation (1) so we have
\[4x + 3y = 36\]
\[\Rightarrow 4\left( {\dfrac{{ - 21}}{2}} \right) + 3\left( {26} \right) = 36 \\
\Rightarrow - 42 + 78 = 36 \\
\Rightarrow 36 = 36 \]
Hence the values of the unknown that are \[x\] and \[y\] are the correct values which satisfy the equation.

Hence, the unknown values \[x\] and \[y\] that are \[\dfrac{{ - 21}}{2}\] and \[26\] respectively.

Note:In this type of question while eliminating the term we must be aware of the sign where we change the sign by the alternate sign. In this we have a chance to verify our answers. In the elimination method we have made the one term have the same coefficient such that it will be easy to solve the equation.