Statement 1: Atom A with 7 valence electrons forms $A{{B}_{2}}$ with atom B with two valence electrons
Statement 2: B donates its electrons to fill the outer shell of A.
A. Statement-1 is true, statement-2 is true and statement-2 is the correct explanation for statement-1.
B. Statement-1 is true, statement-2 is true and statement-2 is NOT the correct explanation for statement-1.
C. Statement-1 is true, statement-2 is false
D. Statement-1 is false, statement-2 is true
E. Both statement 1 and statement 2 are incorrect

Hint: The atom which has eight electrons (octet electronic configuration) in the valence shell is more stable than the atom which does not have octet electronic configuration. Two atoms will combine and form a molecule.

Complete step by step solution: - In the question it is asked to find the correct statements among the given two statements.
- In statement 1 it is given that Atom A with 7 valence electrons forms $A{{B}_{2}}$ with atom B with two valence electrons.
- The atom A does not donate electrons but it accepts one electron to get octet electronic configuration.
- So atom A accepts only one electron.
- Therefore statement A is wrong because there is no chance of formation of $A{{B}_{2}}$ molecule.
- Coming to statement 2, atom B donates its electrons to fill the outer shell of A.
- After accepting electrons from B the atom A is going to form a compound with molecular formula of ${{A}_{2}}B$ .
- Therefore statement 1 is incorrect and statement 2 is correct.

Therefore the correct option is D.

Note: All the atoms in nature try to get the octet electronic configuration by accepting or donating electrons from other or to others. Because of any molecule which contains octet electronic configuration they are more stable.