STATEMENT – 1: The slant height of frustum of cone is 4cm. and perimeter of its circular ends are 18 cm, and 6 cm, then the curved surface area is 48 sq. cm.
STATEMENT – 2: Curved surface area of frustum is $\pi \left( {{r_1} + {r_2}} \right)$ where ${r_1}{\text{ and }}{{\text{r}}_2}$ are the radii of the frustum and l is the slant height.
$
(a){\text{ Statement - 1 is True, Statement - 2 is True, Statement - 2 is a correct explanation for statement - 1}}{\text{.}} \\
(b){\text{ Statement - 1 is True, Statement - 2 is True, Statement - 2 is not a correct explanation for statement - 1}}{\text{.}} \\
(c){\text{ Statement - 1 is True, Statement - 2 is False}} \\
(d){\text{ Statement - 1 is False, Statement - 2 is True}} \\
$
Answer
684.3k+ views
Hint: In this question use the direct formula for the curved surface area of frustum of cone. Curved surface area of frustum of cone$\pi \left( {{r_1} + {r_2}} \right)l$.
Complete step-by-step answer:
As we know that the curved surface area (C.S.A) of the frustum is $\pi \left( {{r_1} + {r_2}} \right)l$ $cm^2$………… (1)
Where r2 and r1 are the radius of lower and upper circular parts.
And l = slant height of the frustum.
So from the above formula of the curved surface area of the frustum clearly that statement – 2 is false as in statement 2 slant height is not present in the formula.
Now according to statement – 1 it is given that slant height (l) = 4 cm.
And the perimeter of the circular ends are 18 and 6 cm respectively.
As we know that the perimeter of a circle is$2\pi r$, where r is the radius of the circle.
So the upper circular part of the circle perimeter is $2\pi {r_1}$
$ \Rightarrow 2\pi {r_1} = 18$
$ \Rightarrow {r_1} = \dfrac{{18}}{{2\pi }}$ cm.
Now the lower circular part of the circle perimeter is $2\pi {r_2}$
$ \Rightarrow 2\pi {r_2} = 6$
$ \Rightarrow {r_2} = \dfrac{6}{{2\pi }}$ cm.
So from equation (1) we have,
$ \Rightarrow C.S.A = \pi \left( {{r_1} + {r_2}} \right)l$
Now substitute all the values in this equation we have,
$ \Rightarrow C.S.A = \pi \left( {\dfrac{{18}}{{2\pi }} + \dfrac{6}{{2\pi }}} \right)4 = \pi \left( {\dfrac{{24}}{{2\pi }}} \right)4 = 12 \times 4 = 48$ sq. cm.
Thus statement – 1 is true.
So statement – 1 is true, statement – 2 is false.
Hence option (c) is correct.
Note: Whenever we face such types of problems the key concept is to have a gist of the direct formula of some of the basic conic sections like frustum of cone, sphere, cylindrical etc. This helps save a lot of time while solving such types of problems.
Complete step-by-step answer:
As we know that the curved surface area (C.S.A) of the frustum is $\pi \left( {{r_1} + {r_2}} \right)l$ $cm^2$………… (1)
Where r2 and r1 are the radius of lower and upper circular parts.
And l = slant height of the frustum.
So from the above formula of the curved surface area of the frustum clearly that statement – 2 is false as in statement 2 slant height is not present in the formula.
Now according to statement – 1 it is given that slant height (l) = 4 cm.
And the perimeter of the circular ends are 18 and 6 cm respectively.
As we know that the perimeter of a circle is$2\pi r$, where r is the radius of the circle.
So the upper circular part of the circle perimeter is $2\pi {r_1}$
$ \Rightarrow 2\pi {r_1} = 18$
$ \Rightarrow {r_1} = \dfrac{{18}}{{2\pi }}$ cm.
Now the lower circular part of the circle perimeter is $2\pi {r_2}$
$ \Rightarrow 2\pi {r_2} = 6$
$ \Rightarrow {r_2} = \dfrac{6}{{2\pi }}$ cm.
So from equation (1) we have,
$ \Rightarrow C.S.A = \pi \left( {{r_1} + {r_2}} \right)l$
Now substitute all the values in this equation we have,
$ \Rightarrow C.S.A = \pi \left( {\dfrac{{18}}{{2\pi }} + \dfrac{6}{{2\pi }}} \right)4 = \pi \left( {\dfrac{{24}}{{2\pi }}} \right)4 = 12 \times 4 = 48$ sq. cm.
Thus statement – 1 is true.
So statement – 1 is true, statement – 2 is false.
Hence option (c) is correct.
Note: Whenever we face such types of problems the key concept is to have a gist of the direct formula of some of the basic conic sections like frustum of cone, sphere, cylindrical etc. This helps save a lot of time while solving such types of problems.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Differentiate between voluntary action and reflex class 10 biology CBSE

The uses of bleaching powder are A It is used bleaching class 10 chemistry CBSE

Fill in the blanks with abstract nouns of the words class 10 english CBSE

How many threedigit numbers are there class 10 maths CBSE

What is a reflex arc class 10 biology CBSE

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

10 examples of evaporation in daily life with explanations

What is the full form of POSCO class 10 social science CBSE

Make a sketch of the human nerve cell What function class 10 biology CBSE

Differentiate between Xylem and phloem class 10 biology CBSE

Identify the feminine form of noun nephew a shenephew class 10 english CBSE

