The average temperature of the first three days of the week is ${{27}^{\circ }}C$ and the next three days is ${{29}^{\circ }}C$. If the weekly average is ${{28.5}^{\circ }}C$, what is the temperature on the last day?
(A) ${{31.5}^{\circ }}C$
(B) ${{28}^{\circ }}C$
(C) ${{21}^{\circ }}C$
(D) ${{42}^{\circ }}C$
Answer
647.7k+ views
Hint: We solve this question by first assuming the temperatures on first three days as ${{x}_{1}},{{x}_{2}},{{x}_{3}}$ and temperatures on next three days as ${{x}_{4}},{{x}_{5}},{{x}_{6}}$ and the temperature on last day as $X$. Then we consider the formula for average, $Average=\dfrac{Sum\ of\,observations}{Total\ number\ of\ observations}$ and find the value of sum of temperatures on the first three days and then sum of temperatures on the next three days. Then we add them to find the value of the sum of temperatures on the first six days. Then we use the same formula to find the sum of temperatures on all seven days. Then we substitute the value of the sum of temperatures on the first six days in the equation obtained and find the value of temperature on the last day.
Complete step by step answer:
We are given that the average temperature of the first three days of the week is ${{27}^{\circ }}C$. Let the temperatures on those days be ${{x}_{1}},{{x}_{2}},{{x}_{3}}$.
We are also given that the average temperature of the next three days of the week is ${{29}^{\circ }}C$. Let the temperatures on those days be ${{x}_{4}},{{x}_{5}},{{x}_{6}}$.
We are also given that the weekly average is ${{28.5}^{\circ }}C$.
We need to find the temperature on the last day. Let that temperature be $X$.
Now let us consider the formula for average.
$Average=\dfrac{Sum\ of\,observations}{Total\ number\ of\ observations}$
As we are given that average temperature of first three days of the week is ${{27}^{\circ }}C$, we can write it as,
$\begin{align}
& \Rightarrow \dfrac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}}{3}=27 \\
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}=81..........\left( 1 \right) \\
\end{align}$
As we are given that average temperature of next three days of the week is ${{29}^{\circ }}C$, we can write it as,
$\begin{align}
& \Rightarrow \dfrac{{{x}_{4}}+{{x}_{5}}+{{x}_{6}}}{3}=29 \\
& \Rightarrow {{x}_{4}}+{{x}_{5}}+{{x}_{6}}=87..........\left( 2 \right) \\
\end{align}$
Now let us add the values from equations (1) and (2). Then we get,
$\begin{align}
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}=81+87 \\
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}=168.........\left( 3 \right) \\
\end{align}$
As we are also given that the weekly average is ${{28.5}^{\circ }}C$, we can write it as,
$\begin{align}
& \Rightarrow \dfrac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}+X}{7}=28.5 \\
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}+X=199.5 \\
\end{align}$
Now let us substitute the value obtained in equation (3) in the above equation. Then we get,
$\begin{align}
& \Rightarrow 168+X=199.5 \\
& \Rightarrow X=199.5-168 \\
& \Rightarrow X=31.5 \\
\end{align}$
So, we get the temperature of the last day as ${{31.5}^{\circ }}C$.
Hence the answer is Option A.
Note:
While solving this question one might wrongly interpret the given information by taking the given information, the average temperature of first three days is ${{27}^{\circ }}C$ as, the temperature on all three days is ${{27}^{\circ }}C$. It gives the same answer but the interpretation is wrong. Here the temperature on the three days can be different but their average is ${{27}^{\circ }}C$.
Complete step by step answer:
We are given that the average temperature of the first three days of the week is ${{27}^{\circ }}C$. Let the temperatures on those days be ${{x}_{1}},{{x}_{2}},{{x}_{3}}$.
We are also given that the average temperature of the next three days of the week is ${{29}^{\circ }}C$. Let the temperatures on those days be ${{x}_{4}},{{x}_{5}},{{x}_{6}}$.
We are also given that the weekly average is ${{28.5}^{\circ }}C$.
We need to find the temperature on the last day. Let that temperature be $X$.
Now let us consider the formula for average.
$Average=\dfrac{Sum\ of\,observations}{Total\ number\ of\ observations}$
As we are given that average temperature of first three days of the week is ${{27}^{\circ }}C$, we can write it as,
$\begin{align}
& \Rightarrow \dfrac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}}{3}=27 \\
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}=81..........\left( 1 \right) \\
\end{align}$
As we are given that average temperature of next three days of the week is ${{29}^{\circ }}C$, we can write it as,
$\begin{align}
& \Rightarrow \dfrac{{{x}_{4}}+{{x}_{5}}+{{x}_{6}}}{3}=29 \\
& \Rightarrow {{x}_{4}}+{{x}_{5}}+{{x}_{6}}=87..........\left( 2 \right) \\
\end{align}$
Now let us add the values from equations (1) and (2). Then we get,
$\begin{align}
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}=81+87 \\
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}=168.........\left( 3 \right) \\
\end{align}$
As we are also given that the weekly average is ${{28.5}^{\circ }}C$, we can write it as,
$\begin{align}
& \Rightarrow \dfrac{{{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}+X}{7}=28.5 \\
& \Rightarrow {{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}+{{x}_{6}}+X=199.5 \\
\end{align}$
Now let us substitute the value obtained in equation (3) in the above equation. Then we get,
$\begin{align}
& \Rightarrow 168+X=199.5 \\
& \Rightarrow X=199.5-168 \\
& \Rightarrow X=31.5 \\
\end{align}$
So, we get the temperature of the last day as ${{31.5}^{\circ }}C$.
Hence the answer is Option A.
Note:
While solving this question one might wrongly interpret the given information by taking the given information, the average temperature of first three days is ${{27}^{\circ }}C$ as, the temperature on all three days is ${{27}^{\circ }}C$. It gives the same answer but the interpretation is wrong. Here the temperature on the three days can be different but their average is ${{27}^{\circ }}C$.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

