The compound most likely to decolorize a solution of potassium permanganate is
A.
B.
C.
D.
Answer
300.9k+ views
Hint: Potassium permanganate is an inorganic compound having the chemical formula . It is a purple solution.
This solution is decolorized in the presence of double or triple bonds.
Complete Step by Step Solution:
Potassium permanganate is an inorganic compound possessing the chemical formula KMnO4.
It is a purplish-black crystalline salt and undergoes dissolution in water as and as a result, its solution is pink or purple.
Dilute solutions of transforming alkenes into diols (glycols).
This reaction is also utilised as a qualitative test for the presence of double or triple bonds in a molecule.
Hence, called Baeyer's reagent.
The decolorization occurs as originally purple permanganate solution after reaction generates a brown precipitate of Manganese dioxide.
The oxidation state of manganese is +7 and it gets reduced to +4 in. It undergoes reduction and oxidises the double and triple bonds leading to the formation of single bonds.
We have to find out which of the given options will decolorize potassium permanganate.
A.
This compound only contains single bonds. Hence, it will not decolorize the solution of potassium permanganate.
So, A is incorrect.
B.
This is the structure of Naphthalene. This will not decolorize potassium permanganate as it is an aromatic compound and the double bond here is delocalized.
So, B is incorrect.
C.
This compound contains a double bond which can be attacked by potassium permanganate and eventually will get oxidised.
So, this will decolorize the solution of potassium permanganate.
So, C is correct.
D.
This compound only contains single bonds. Hence, it will not decolorize the solution of potassium permanganate.
So, D is incorrect.
So, option C is correct.
Note: Still it must be remarked that bromine acts as a better reagent in estimating the presence of unsaturation i.e., double or triple bonds quantitatively. This is because , being an extremely strong oxidising agent, it can react with groups other than compounds having double and triple bonds.
This solution is decolorized in the presence of double or triple bonds.
Complete Step by Step Solution:
Potassium permanganate is an inorganic compound possessing the chemical formula KMnO4.
It is a purplish-black crystalline salt and undergoes dissolution in water as and as a result, its solution is pink or purple.
Dilute solutions of transforming alkenes into diols (glycols).
This reaction is also utilised as a qualitative test for the presence of double or triple bonds in a molecule.
Hence, called Baeyer's reagent.
The decolorization occurs as originally purple permanganate solution after reaction generates a brown precipitate of Manganese dioxide.
The oxidation state of manganese is +7 and it gets reduced to +4 in. It undergoes reduction and oxidises the double and triple bonds leading to the formation of single bonds.
We have to find out which of the given options will decolorize potassium permanganate.
A.
This compound only contains single bonds. Hence, it will not decolorize the solution of potassium permanganate.
So, A is incorrect.
B.
This is the structure of Naphthalene. This will not decolorize potassium permanganate as it is an aromatic compound and the double bond here is delocalized.
So, B is incorrect.
C.
This compound contains a double bond which can be attacked by potassium permanganate and eventually will get oxidised.
So, this will decolorize the solution of potassium permanganate.
So, C is correct.
D.
This compound only contains single bonds. Hence, it will not decolorize the solution of potassium permanganate.
So, D is incorrect.
So, option C is correct.
Note: Still it must be remarked that bromine acts as a better reagent in estimating the presence of unsaturation i.e., double or triple bonds quantitatively. This is because , being an extremely strong oxidising agent, it can react with groups other than compounds having double and triple bonds.
Recently Updated Pages
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main

What is isoelectric point class 12 chemistry JEE_Main

Chlorobenzene is extremely less reactive towards a class 12 chemistry JEE_Main

In order to convert Aniline into chlorobenzene the class 12 chemistry JEE_Main

Give one chemical test to distinguish between the following class 12 chemistry JEE_Main

The coordination number of an atom in a fcc lattice class 12 chemistry JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
NCERT Solutions For Class 12 Chemistry Chapter 2 Electrochemistry - 2026-27 Free PDF Download (Sign-in Required)

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2026-27 Free PDF Download (Sign-in Required)

NCERT Solutions For Class 12 Chemistry Chapter 3 Chemical Kinetics - 2026-27 Free PDF Download (Login Required)

CBSE Notes Class 12 Chemistry Chapter 1 - Solutions - 2026-27 PDF Download (Login Required)

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes - 2026-27 Free PDF Download (Sign-In Required)

NCERT Solutions For Class 12 Chemistry Chapter 7 Alcohol Phenol And Ether - 2026-27 Free PDF Download (Login Required)

