The IUPAC name of the following compound is 4-(ethoxycarbonyl) benzoic acid.

   (A)True
   (B)False

Hint: First choose the longest carbon chain to be the parent chain and then see which of the functional groups is of highest priority. Start numbering the chain from the position of most prior functional groups towards the substituent.

Complete answer:
-The first step in IUPAC nomenclature is identifying the longest carbon chain.
Here the longest chain is the 6 carbon cyclic structure benzene.
Also, in the given structure there are 2 functional groups. They are carboxylic acid and ester group out of which carboxylic acid is of highest priority and thus the major functional group.
So, the parent chain will be the benzene with carboxylic acid which is called benzoic acid.
-Now we will look at the substituent group. In this there is an ethyl group attached to the oxygen atom of the carbonyl group and so it will be known as ethoxycarbonyl.
This ethoxycarbonyl group is attached at 4th position while numbering from position of carboxylic acid. The numbering will be done as follows:

So, the IUPAC name of this structure will be 4-(ethoxycarbonyl) benzoic acid. It has a molecular formula of: ${C_{10}}{H_{10}}{O_4}$.

Hence the correct option is: (A) True.

Note:
The priority order of the functional groups is: carboxylic acid > sulfonic acid > ester > acid halide > amide > nitrile > aldehyde > ketone > alcohol > thiol > amine. If any compound has two or more functional groups the numbering is always done on the basis of the priority of the functional groups.