The line \[2y - 5 = 0\] is parallel to the \[x\] axis. If true enter 1 else 0.
Answer
620.7k+ views
Hint: Here we will use the basic Cartesian plane to draw the line on the graph. First, we will modify the equation to get it in the linear form. So, we will draw the line with the given equation to find whether the line is parallel to the X-axis or not.
Complete step by step solution:
The given equation of the line is \[2y - 5 = 0\].
First, we will rewrite the given equation to get it in the linear form. Therefore, we get
\[ \Rightarrow 2y = 5\]
\[ \Rightarrow y = \dfrac{5}{2} = 2.5\]
We can see that in the linear equation of the line there is no term of \[x\] which means that for any value of \[x\] the value of \[y\] remains constant. So we will plot this lint on the Cartesian plane.
It is given that the line is passing through the point having \[y\] coordinates as \[2.5\]. The line will be passing through the point which is at a distance of \[2.5\] on the Y-axis from the origin. This line will be parallel to the X-axis as the value of \[y\] will be constant irrespective of the value of \[x\].
Hence, on the above graph line \[2y - 5 = 0\] is represented.
Note:
We should know that this axis is the infinite lines in the Cartesian plane. While writing the coordinates of a point always the X-axis intercept of the point is written first and then the Y-axis intercept is written. Also in the representation of this axis in the Cartesian plane are perpendicular to each other and intersecting at a point which is named as the origin. We should remember that the positive X-axis is towards the right side of the origin and the negative X-axis is towards the left side of the origin. Also the positive Y-axis is towards the upward direction from the origin and negative Y-axis is towards the downward direction from the origin.
Complete step by step solution:
The given equation of the line is \[2y - 5 = 0\].
First, we will rewrite the given equation to get it in the linear form. Therefore, we get
\[ \Rightarrow 2y = 5\]
\[ \Rightarrow y = \dfrac{5}{2} = 2.5\]
We can see that in the linear equation of the line there is no term of \[x\] which means that for any value of \[x\] the value of \[y\] remains constant. So we will plot this lint on the Cartesian plane.
It is given that the line is passing through the point having \[y\] coordinates as \[2.5\]. The line will be passing through the point which is at a distance of \[2.5\] on the Y-axis from the origin. This line will be parallel to the X-axis as the value of \[y\] will be constant irrespective of the value of \[x\].
Hence, on the above graph line \[2y - 5 = 0\] is represented.
Note:
We should know that this axis is the infinite lines in the Cartesian plane. While writing the coordinates of a point always the X-axis intercept of the point is written first and then the Y-axis intercept is written. Also in the representation of this axis in the Cartesian plane are perpendicular to each other and intersecting at a point which is named as the origin. We should remember that the positive X-axis is towards the right side of the origin and the negative X-axis is towards the left side of the origin. Also the positive Y-axis is towards the upward direction from the origin and negative Y-axis is towards the downward direction from the origin.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

