The population of a town increases \[5\% \] every year. If the present population is 180800. Find the population after a year.

Hint: First of all, find the increase in the population every year. Then the population after a year is the sum of the present population and the increase in the population every year.

Complete step-by-step answer:
Given present population of a town is 180800
Population of the town increases every year at the rate of \[5\% \]
 So, \[5\% \] of 180800 is given by
\[
   = \dfrac{5}{{100}} \times 180800 \\
   = 5 \times 1808 \\
   = 9040 \\
\]
Hence the population of the town increases by 9040 every year.
Therefore, the population after a year = present population + increase in population every year
                                                                     = 180800 + 9040
                                                                     = 189840
Thus, the population of the town after a year is 189840.

Note: The population after a year must be more than the present population as there is an increase in the population of every year in the town. The \[x\% \] of \[y\] is given by \[\dfrac{x}{{100}} \times y\].