The sum of two consecutive integers is 47, how do you find the two numbers?

Hint: First we assume the two consecutive numbers are $x$ and $x + 1$ . Then as given in the question the sum of these two numbers is 47, so we add the assumed numbers and equate the sum to 47. Then solve the equation formed to obtain the desired answer.

Complete step-by-step answer:
We have been given that the sum of two consecutive numbers is 47.
We have to find the numbers.
The numbers that follow each other continuously in the order from smallest to largest are called consecutive numbers. For example, 1, 2, 3, 4, and so on are consecutive numbers.
Now, let us assume the two consecutive numbers are $x$ and $x + 1$.
Now, according to the question, the sum of these two numbers is 47, then we have
$ \Rightarrow x + \left( {x + 1} \right) = 47$
Now, simplify the above equation we get
$ \Rightarrow 2x + 1 = 47$
Move constant part on the right side of the equation,
$ \Rightarrow 2x = 47 - 1$
Subtract the terms on the right side,
$ \Rightarrow 2x = 46$
Divide both sides by 2,
$ \Rightarrow x = 23$
So, the first number is 23.
Now, the second number will be $23 + 1 = 24$.

Hence, the two consecutive numbers are 23 and 24.

Note:
The consecutive numbers follow each other in order, without gaps, and from the smallest number to the largest number. To understand consecutive numbers, we will first need to understand the concept of predecessors and successors. The number that is written immediately before a number is called a predecessor. The number that is written immediately after a number is called its successor.
Fun facts: the sum of two consecutive numbers is always odd.
Example 1: 3 + 4 = 7
Example 2: (-8) + (-7) = -15