Using a number line, write the integer which is $3$ more than $ - 7$ .

Hint: In this question, we are given a number $ - 7$ and using a number line, we have to mark a point that is $3$ more than $ - 7$ , i.e., three numbers ahead of $ - 7$ .
We know that on a number line, the numbers increase as we move from left to right.
So, in this, first, we will draw a number line, mark the point $ - 7$ on it and then move three steps towards the right side.

Complete step by step solution:
We are given a number $ - 7$ .
We have to find a number which is three times more than $ - 7$ , using a number line.
So first we will draw a number line and mark a point $A$ on it, which is our point $ - 7$ .

Now, we have to move forward by three steps.

And we get the point $ - 4$ , mark it as $B$ .

Hence, we get the point $ - 4$ , as we move by three steps on the right side of $ - 7$ .

Note: One must remember that when we start counting the numbers, our step is the nest number which is written beside the actual number and not that same number. For example, in this question, after the first step, we get the number $ - 6$ and not the number $ - 7$ itself.
We can solve this question even without using the number line, in this, we have to write a number which is three more than $ - 7$ , i.e., we just have to add $3$ in it, so we get, $ - 7 + 3$ which gives $ - 4$ .
For this, we must know the operations that positive and positive is positive, negative and negative is again positive, positive and negative is negative and at last negative and positive is again negative, which can be written mathematically as
\[ + + = + \]
\[ - - = + \]
\[ + - = - \]
\[ - + = - \]