What is the mean of \[24,36,48\] and \[60\]?

Hint: The mean is the most commonly used measure of central tendency. The mean is classified as arithmetic mean(A.M) , weighted mean, geometric mean (G.M) and harmonic mean (H.M). We commonly prefer arithmetic mean methods.
Formula to be used:
Mean $\overline x $ $ = \dfrac{{{x_1} + {x_2} + ...... + {x_n}}}{n}$
Where,
${x_i}$($1 \leqslant i \leqslant n$) denotes each value of the given set of data,
 and $n$ is the total number of observations in the given collection of data

Complete step-by-step solution:
The mean generally refers to an average of the given collection of data. We generally prefer the method of arithmetic mean. Now, we are going to apply the arithmetic mean method for this problem. The arithmetic mean is the ratio of the total of the sum of each value in the given collection of data to the total number of observations in a collection. From the given information. We consider a collection of data containing \[24,36,48\] and \[60\].
(i.e.) ${x_1} = 24$ ,${x_2} = 36$ ,${x_3} = 48$ and ${x_4} = 60$ .
And, the total number of observations, $n = 4$ .
We know that the formula then calculates the mean for three values which is as follows.
Mean$ = \dfrac{{{x_1} + {x_2} + {x_3}}}{3}$
We need to substitute the above values in the formula, we have
$Mean = \dfrac{{24 + 36 + 48+60}}{4}$ ,
 $ = \dfrac{{168}}{4}$
$ = 42$
(i.e.), Mean $\overline x = 42$ which is the required solution.
Hence, the mean of \[24,36,48\] and \[60\] is 42.

Note: First of all, the term central tendency is the statistical term is the single value which acts as a representative of the data. There are three commonly used measures of central tendency (i.e.) the mean, the median and the mode are the most commonly used measures of central tendency.