Which one of the following is a planar molecule
A. \[NH_3\]
B. \[H_3O^{+}\]
C. \[BCl_3\]
D. \[PCl_3\]
Answer
300.9k+ views
Hint: Trigonal planar structure is depicted by a molecule having one central atom bound to the other three atoms resembling the corner of an equilateral triangle. The bond angles are \[120^o\].
Complete step by step solution:Here in this question, we have to find out which of the following molecules has a planar structure.
A. \[NH_3\]
Here N is the central atom. Nitrogen has five electrons in its valence shell.
Three electrons are involved in bond-making and two other electrons pair up.
So, it has three bond pairs and one lone pair.
So, it has a trigonal pyramidal structure.
So, A is incorrect.
B. \[H_3O^{+}\]
Here O is the central atom. It has a positive charge and thus has five electrons in this valence shell.
Three electrons bond with three electrons each from a hydrogen atom. One lone pair is present.
So, there are three bond pairs and one lone pair.
So, it has a trigonal pyramidal structure.
So, B is incorrect.
C. \[BCl_3\]
Here Boron is the central atom.
It includes three electrons in its valence shell.
Three electrons are involved in bond-making.
So, it has three bond pairs.
So, it has a trigonal planar structure.

Image: Structure of BCl3
So, C is correct.
D. \[PCl_3\]
Here P is the central atom. It includes five electrons in its valence shell.
Three electrons are involved in bond-making and two other electrons pair up.
So, it has three bond pairs and one lone pair.
So, it has a trigonal pyramidal structure.
So, D is incorrect.
So, option C is correct.
Note: In chemistry, hydronium is the common name for the aqueous cation H3O+.
It is usually considered as the positive ion present when an Arrhenius acid undergoes dissolution in water.
Arrhenius acid molecules in solution lose proton \[H^+\] to the surrounding water molecules forming hydronium ions.
Complete step by step solution:Here in this question, we have to find out which of the following molecules has a planar structure.
A. \[NH_3\]
Here N is the central atom. Nitrogen has five electrons in its valence shell.
Three electrons are involved in bond-making and two other electrons pair up.
So, it has three bond pairs and one lone pair.
So, it has a trigonal pyramidal structure.
So, A is incorrect.
B. \[H_3O^{+}\]
Here O is the central atom. It has a positive charge and thus has five electrons in this valence shell.
Three electrons bond with three electrons each from a hydrogen atom. One lone pair is present.
So, there are three bond pairs and one lone pair.
So, it has a trigonal pyramidal structure.
So, B is incorrect.
C. \[BCl_3\]
Here Boron is the central atom.
It includes three electrons in its valence shell.
Three electrons are involved in bond-making.
So, it has three bond pairs.
So, it has a trigonal planar structure.

Image: Structure of BCl3
So, C is correct.
D. \[PCl_3\]
Here P is the central atom. It includes five electrons in its valence shell.
Three electrons are involved in bond-making and two other electrons pair up.
So, it has three bond pairs and one lone pair.
So, it has a trigonal pyramidal structure.
So, D is incorrect.
So, option C is correct.
Note: In chemistry, hydronium is the common name for the aqueous cation H3O+.
It is usually considered as the positive ion present when an Arrhenius acid undergoes dissolution in water.
Arrhenius acid molecules in solution lose proton \[H^+\] to the surrounding water molecules forming hydronium ions.
Recently Updated Pages
Normality of 03 M phosphorus acid H3PO3 is A 05 B 06 class 11 chemistry JEE_Main

A molecule with highest bond energy A Fluorine B Chlorine class 11 chemistry JEE_Main

A 30 solution of H2O2 is marketed as 100 volume hydrogen class 11 chemistry JEE_Main

Covalent compounds generally have low melting and boiling class 11 chemistry JEE_Main

When an acid reacts with a metal carbonate or metal class 11 chemistry JEE_Main

The degeneracy of hydrogen atom that has equal energy class 11 chemistry JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

NCERT Solutions For Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts Of Chemistry - 2026-27 Free PDF Download (Sign-in Required)

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Different Types of Solutions in Chemistry

Effective Nuclear Charge for JEE

CBSE Notes Class 11 Chemistry Chapter 5 - Thermodynamics - 2026-27 PDF Download (Login Required)

