When work done by a system was $10J$ , the increase in the internal energy of the system was $30J$. The heat q supplied to the system was.
A) $10J$
B) $20J$
C) $30J$
D) None of these

Hint:We know the First Law of thermodynamics,
The first law of thermodynamics expresses that energy can be changed over beginning with one structure then onto the following yet it can't be made nor crushed.
The numerical expression is,
$\Delta E = - q + w$
Where,
$\Delta E$ is the change in internal energy.
q is the amount of heat exchanged.
w is the work done by the system.

Complete step by step answer:
From first law of thermodynamics,
\[\Delta U = q + W\]
\[ \Rightarrow q = \Delta U - W\]
As the work is finished by the framework and the inner energy is expanded.
In this manner,
$W = - 10J$
$\Delta U = 30J$
$q = 30 - \left( { - 10} \right) = 40$
Henceforth the warmth provided to the framework is $40J$ .
Hence option D is correct.
Additional Note:
We as a whole know the mathematical articulation of first law thermodynamics,
$\Delta E = q + w$
An adiabatic cycle is one in which no glow is gotten or lost by the structure. The chief law of thermodynamics shows that all the adjustment in inside energy is as work done. In this way, from the main law thermodynamics,
$\Delta E = q + W = 0 + W$
$\Delta E = W$
In this way the change in inward energy is equivalent to the measure of work done on the framework yet it isn't identical to zero.
Therefore, Option A is the correct answer.

Note:
One can determine the internal energy for one mole of carbon monoxide using the first law of thermodynamics.The four fundamental laws of thermodynamics express empirical facts and define physical quantities, such as temperature, heat, thermodynamic work, and entropy, that characterize thermodynamic processes and thermodynamic systems in thermodynamic equilibrium.