How do you write the equation for this reaction: Nitrogen gas and fluorine gas combine to produce nitrogen trifluoride gas?

Hint The general concept of the chemistry which tells about how to write a balanced chemical equation where the number of moles of each atom in the reactant side should equal to that in the product side. Write the above equation in a correct format and then balance the equation.

Complete step – by – step answer:
In the previous classes of chemistry, we have studied in detail about how to write the reactions with the given data and also about balancing the given chemical equation.
We shall now see how to write the above given data in the form of a chemical equation and balancing it.
- A chemical equation is the interpretation of the substances which reacts together to form a new or modified substance.
- The compounds which react with each other are called reactants and the compounds which are newly formed are called as the products.
- The reactants that are written on the left hand side of the reaction and products on the right hand side of the equation which is separated by an arrow that represents the reaction going from hand right to left hand side.
- Balancing of this chemical equation is nothing but making the number of moles of each atom on the reactant side to be equal to that of the product side.
Now, in above data nitrogen reacts with fluorine to give nitrogen trifluoride where the reaction in simple way can be written as,
$ {{N}_{2}}(g)+{{F}_{2}}(g)\to N{{F}_{3}}(g)$
This, reaction have to be balanced and the balanced equation thus is written as,
$ {{N}_{2}}(g)+3{{F}_{2}}(g)\to 2N{{F}_{3}}(g)$
Thus, the above equation is the required answer.

Note: Note that the balancing of a chemical equation need not be necessarily in integer form but can also be in the fraction form. The above reaction can also be written in the fraction balanced form as $ \dfrac{1}{2}{{N}_{2}}(g)+\dfrac{3}{2}{{F}_{2}}(g)\to N{{F}_{3}}(g)$