How do you write the equation \[y + 3 = - 5(x + 1)\] in standard form?

Hint: In this question we have simplified the given trigonometric form. Next, we use some trigonometric identities and then simplify to arrive at our final answer. Next, we rearrange the trigonometric functions .And also we are going to add and subtraction in complete step by step solution.
The standard form of a linear equation is: \[Ax + By = C\]
Where, if at all possible, A, B, and Care integers, and A is non-negative, and, A, B, and C have no common factors other than 1.

Complete step by step answer:
Given,
Rearrange \[y + 3 = - 5(x + 1)\] into this form distribute bracket
\[ \Rightarrow y + 3 = - 5x - 5\]
Add \[5x\] to both sides and we get
\[ \Rightarrow 5x + y + 3 = - 5\not{x} + 5\not{x} - 5\]
Subtract 3 from both sides and we get
\[ \Rightarrow 5x + y + 3 - 3 = - 5 - 3\]
Cancel the opposite sign and we get
\[ \Rightarrow 5x + y + \not{3} - \not{3} = - 5 - 3\]
\[ \Rightarrow 5x + y = - 8\]

This is the required standard form.5x + y = - 8

Note: We have to remember that, Standard form is another way to write slope-intercept form (as opposed to\[y = mx + b\]). It is written as \[Ax + By = C\]. A, B, C are integers (positive or negative whole numbers). No fraction decimals in standard form. "\[Ax\]" term is positive.
Point-slope is a specific form of linear equations in two variables:
\[ \Rightarrow y = mx + b\]
When an equation is written in this form, m gives the slope of the line and $\left( {a,b} \right)$ is a point the line passes through.
This form is derived from the slope formula.
Linear equations are equations that when graphed create a line. Every point on the line is a solution to the equation. Before learning how to create the equation, you should have learned about how to find solutions and graph the equation.
When we have a linear equation in point-slope form, we can quickly find the slope of the corresponding line and a point it passes through. This also allows us to graph it.